A) \[{{C}_{3}}{{H}_{8}}O\]
B) \[{{C}_{2}}{{H}_{4}}{{O}_{2}}\]
C) \[C{{H}_{2}}O\]
D) \[{{C}_{4}}{{H}_{6}}O\]
Correct Answer: B
Solution :
: Percentage of \[C=\frac{12}{44}\times \frac{0.44}{0.30}\times 100=40%\] Percentage of \[H=\frac{2}{18}\times \frac{0.18}{0.30}\times 100=6.6%\] Percentage of \[O=100-(40+6.6)=53.4%\]Element | % | Molar Ratio | Simplest ratio |
C | \[40\] | \[\frac{40}{12}=3.3\] | \[\frac{3.3}{3.3}=1\] |
H | \[6.6\] | \[\frac{6.6}{1}=6.6\] | \[\frac{6.6}{3.3}=2\] |
O | \[53.4\] | \[\frac{53.4}{16}=3.3\] | \[\frac{3.3}{3.3}=1\] |
You need to login to perform this action.
You will be redirected in
3 sec