A) 0.49 N vertically downwards
B) 9.8 N vertically downwards
C) 0.49 N vertically upwards
D) 0.98 N vertically downwards
Correct Answer: A
Solution :
: Here, Mass of the stone, \[m=0.05\text{ }kg\] The magnitude of net force on the stone is \[F=mg=(0.05kg)(9.8m\,{{s}^{-2}})=0.49N\] Its direction is vertically downwards.You need to login to perform this action.
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