A) \[5050\Omega \]
B) \[5950\Omega \]
C) \[595\Omega \]
D) \[5059\Omega \]
Correct Answer: B
Solution :
: Here, Resistance of galvanometer, \[G=50\Omega \]. Current for full scale deflection, \[{{I}_{g}}=5\times {{10}^{-4}}A\] Let R be resistance connected in series with the galvanometer to read 3 V. Then \[V={{I}_{g}}(G+R)\] or \[R=\frac{V}{{{I}_{g}}}-G\] \[R=\frac{3V}{5\times {{10}^{-4}}}-50\Omega \] \[=6000\Omega -50\Omega =5950\Omega \]You need to login to perform this action.
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