A) \[4E\]and \[2r\]
B) \[2E\] and \[2r\]
C) \[4E\] and \[4r\]
D) \[2E\] and \[4r\]
Correct Answer: D
Solution :
: When all cells are connected correctly, then equivalent emf of the combination is \[{{E}_{eq}}=4E\] and effective internal resistance of the combination is \[{{r}_{eff}}=4r\] As one wrongly connected cell decreases the equivalent emf by 2E whereas effective internal resistance remains the same. So \[{{E}_{eq}}=4E-2E=2E\] and \[{{r}_{eff}}=4r\]s
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