A) \[T=\frac{1}{2\pi }\sqrt{\frac{I}{MB}}\]
B) \[T=2\pi \sqrt{\frac{MB}{I}}\]
C) \[T=\frac{1}{2\pi }\sqrt{\frac{MB}{I}}\]
D) \[T=2\pi \sqrt{\frac{I}{MB}}\]
Correct Answer: D
Solution :
: The time period of a magnet executing SHM is \[T=2\pi \sqrt{\frac{I}{MB}}\] Where \[I\] is the moment of inertia of the magnet, M is its magnetic moment and B is an external magnetic field.
You need to login to perform this action.
You will be redirected in
3 sec
