A) \[2\Omega \]
B) \[6\Omega \]
C) \[1\Omega \]
D) \[4\Omega \]
Correct Answer: B
Solution :
: Let X be the resistance with which S is to be shunted for the bridge to be balanced. Then, for balanced Wheatstones bridge \[\frac{P}{Q}=\frac{R}{\frac{SX}{S+X}}\](\[\because \] S and X are in parallel) Substituting the given values, we get \[\frac{2\Omega }{2\Omega }=\frac{2\Omega }{\frac{(3\Omega )X}{3\Omega +X}}\] or \[\frac{(3\Omega )X}{3\Omega +X}=2\Omega \] \[(3\Omega )X=(2\Omega )(3\Omega )+(2\Omega )X\] \[X(3\Omega -2\Omega )=(2\Omega )\,(3\Omega )\] \[X(1\,\Omega )=(2\Omega )\,(3\Omega )\] \[X=\frac{(2\Omega )\,\,(3\Omega )}{1\Omega }=6\Omega \]You need to login to perform this action.
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