A) \[25%\]
B) \[40%\]
C) \[50%\]
D) \[75%\]
Correct Answer: B
Solution :
: The efficiency of a Carnot engine is \[\eta =1-\frac{{{T}_{2}}}{{{T}_{1}}}\] Here, \[{{T}_{1}}=500K,\,\,{{T}_{2}}=300K\] \[\therefore \] \[\eta =1-\frac{300K}{500K}=\frac{500K-300K}{500K}\] \[=\frac{200K}{500K}=\frac{2}{5}=\frac{2}{5}\times 100%=40%\]You need to login to perform this action.
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