CET Karnataka Medical CET - Karnataka Medical Solved Paper-2015

  • question_answer
    After adding non-volatile solute freezing point of water decreases to\[-{{0.186}^{o}}C\]. Calculate \[\Delta {{T}_{b}}\], if \[{{K}_{f}}\text{=}1.86\text{ }K\text{ }kg\text{ }mo{{l}^{-1}}\]and \[{{K}_{f}}\text{=}1.86\text{ }K\text{ }kg\text{ }mo{{l}^{-1}}\]

    A)  \[0.0521K\]

    B)  \[0.0186K\]

    C)  \[0.521K\]

    D)  \[1.86K\]

    Correct Answer: A

    Solution :

    : \[\Delta {{T}_{f}}=T_{f}^{o}-{{T}_{f}}=0-(-0.186)={{0.186}^{o}}C\] \[\Delta {{T}_{f}}={{K}_{f}}\times m\] \[\Rightarrow \] \[m=\frac{\Delta {{T}_{f}}}{{{K}_{f}}}=\frac{0.186}{1.86}=0.1m\] \[\Delta {{T}_{b}}={{K}_{b}}\times m=0.521\times 0.1=0.0521K\]


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