A) higher concentration of \[{{H}^{+}}\]
B) lower concentration of \[{{H}^{+}}\]
C) higher concentration of \[{{S}^{2-}}\]
D) lower concentration of \[{{S}^{2-}}\].
Correct Answer: D
Solution :
: Dissociation of \[{{H}_{2}}S\] is suppressed in presence of \[HCl\] due to common ion effect. This decreases the \[{{S}^{2-}}\] ion concentration and hence, only group II radicals having low solubility product are precipitated.You need to login to perform this action.
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