A) 20 A, 220V
B) 0.4 A, 22000V
C) 40 A, 220 V
D) 40 A, 22000 V
Correct Answer: C
Solution :
\[\frac{{{e}_{s}}}{{{e}_{p}}}=\frac{{{N}_{s}}}{{{N}_{p}}}\] Given, \[{{N}_{s}}=500,\]\[{{N}_{p}}=5000,\]\[{{e}_{p}}=2200V\] \[\therefore \] \[{{e}_{s}}=\frac{{{N}_{s}}}{{{N}_{p}}}\times {{e}_{p}}\] \[=\frac{500}{5000}\times 2200=220V\] Again \[\frac{{{e}_{s}}}{{{e}_{p}}}=\frac{{{I}_{p}}}{{{I}_{s}}}\] or \[{{I}_{s}}=4\times \frac{2200}{220}=40A\]You need to login to perform this action.
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