A) \[4{{p}_{0}}\]
B) \[{{p}_{0}}/2\]
C) \[{{p}_{0}}\]
D) \[2{{p}_{0}}\]
Correct Answer: D
Solution :
According to the kinetic theory of gases \[{{p}_{0}}=\frac{mN{{{\bar{c}}}^{2}}}{3V}\] So, resultant pressure \[p=\frac{(m/2)N{{(2\bar{c})}^{2}}}{3V}\] \[=\frac{2mN{{{\bar{c}}}^{2}}}{3V}\] \[=2{{p}_{0}}\]You need to login to perform this action.
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