A) 1 A towards right
B) 0.66 A towards right
C) 0.66 A towards left
D) zero
Correct Answer: B
Solution :
In the two cases current is flowing in the right direction, therefore total current \[I={{I}_{N{{e}^{+}}}}+{{I}_{e}}\] or \[I=({{N}_{N{{e}^{+}}}}+{{N}_{e}})e\] or \[I=(2.9\times {{10}^{18}}+1.2\times {{10}^{18}})\times 1.6\times {{10}^{-19}}\] \[\Rightarrow \] \[I=0.66A\] A towards rightYou need to login to perform this action.
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