A) \[{{B}_{0}}\]
B) \[\sqrt{2}{{B}_{0}}\]
C) \[2B_{0}^{{}}\]
D) \[B_{0}^{2}\]
Correct Answer: B
Solution :
\[{{B}_{0}}=\,B\,\,\cos \,\theta \] or \[B=\frac{{{B}_{0}}}{\cos \,\theta }=\frac{{{B}_{0}}}{\cos \,{{45}^{o}}}=\sqrt{2}{{B}_{0}}\]You need to login to perform this action.
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