A) charge on plates decreases
B) charge on plates does not change , potential difference increases
C) charge on plates does not change? potential difference decreases and energy stored decreases
D) charge on plates does not change, potential difference increases and energy stored also increases
Correct Answer: C
Solution :
When a dielectric slab is kept between a parallel plate capacitor, then (i) Charge stored remains steady (ii) Potential decreases to V/K (iii) Capacitance increases to KC (iv) Energy decreases to U/KYou need to login to perform this action.
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