A) \[{{C}_{2}}{{H}_{4}}\]
B) \[{{C}_{2}}{{H}_{6}}\]
C) \[{{C}_{2}}{{H}_{2}}\]
D) \[C{{H}_{4}}\]
Correct Answer: A
Solution :
\[C%=85.72%,\] (given)\[H%=100-85.72=14.28%\]Elements | % | Atomic Weight | Relative No of atoms | Simples ratio |
\[C\] | \[85.72\] | \[12\] | \[\frac{85.72}{12}=7.14\] | \[\frac{7.14}{7.14}=1\] |
\[H\] | \[14.28\] | \[1\] | \[\frac{14.2}{1}=14.2\] | \[\frac{14.2}{7.14}=2\] |
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