A) \[C{{u}^{+}}\]
B) \[Z{{n}^{2+}}\]
C) \[A{{g}^{+}}\]
D) \[F{{e}^{2+}}\]
Correct Answer: D
Solution :
The ion which contains unpaired electrons gives coloured solution. Among the given only\[F{{e}^{2+}}\]contains 4 unpaired electrons as \[_{26}Fe=1{{s}^{2}},2{{s}^{2}}2{{p}^{6}},3{{s}^{2}}3{{p}^{6}}3{{d}^{6}},4{{s}^{2}}\] \[_{26}F{{e}^{2+}}=1{{s}^{2}},2{{s}^{2}}2{{p}^{6}},3{{s}^{2}}3{{p}^{6}}3{{d}^{6}},4{{s}^{0}}\] Hence, it gives coloured solution.You need to login to perform this action.
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