A) increase by 1%
B) increase by 0.5%
C) decrease by 1%
D) decrease by 0.5%
Correct Answer: B
Solution :
Orbital speed \[v=\sqrt{\frac{GM}{R}}\] By power law of error \[\frac{\Delta v}{v}=-\frac{1}{2}\frac{\Delta R}{R}\] So, \[1%\] decrease in orbital radius will result ii \[0.5%\]increase of the speed of the satellite.You need to login to perform this action.
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