A) \[R\text{/ }\!\!\gamma\!\!\text{ }-1({{T}_{2}}-{{T}_{1}})\]
B) \[R\text{/ }\!\!\gamma\!\!\text{ }-1({{T}_{1}}-{{T}_{2}})\]
C) \[R({{T}_{2}}-{{T}_{1}})\]
D) zero
Correct Answer: A
Solution :
In an adiabatic expansion \[dQ=0\] So, \[d=-dW\] Work done in adiabatic process \[dW=\frac{R}{1-\gamma }({{T}_{2}}-{{T}_{1}})\] \[\therefore \]Change in internal energy \[dU=\frac{-R}{1-\gamma }({{T}_{2}}-{{T}_{1}})\] or \[dU=\frac{R}{1-\gamma }({{T}_{2}}-{{T}_{1}})\]You need to login to perform this action.
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