A) \[C{{H}_{2}}\]
B) \[C{{H}_{2}}O\]
C) \[{{C}_{3}}{{H}_{6}}{{O}_{3}}\]
D) \[{{C}_{2}}{{H}_{4}}{{O}_{2}}\]
Correct Answer: B
Solution :
\[C=40%,\] \[H=6.7%\] \[0%=100-(40\text{ }+\text{ }6.7)\] \[0%=100-46.7=53.3%\]Element | % | Atomic weight | Relative no of otoms | Simple ration of atom |
\[C\] | \[40\] | \[12\] | \[\frac{40}{12}=3.33\] | \[\frac{3.33}{3.33}=1\] |
\[H\] | \[6.7\] | \[1\] | \[\frac{6.7}{1}=6.7\] | \[\frac{6.7}{3.33}=2\] |
\[O\] | \[53.3\] | \[16\] | \[\frac{53.3}{16}=3.33\] | \[\frac{3.33}{3.33}=1\] |
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