A) 5/2,2/5
B) 5/2,5/2
C) 2/5, 5/2
D) 2/5, 2/5
Correct Answer: A
Solution :
In parallel \[\therefore \] \[{{H}_{1}}=\frac{{{V}^{2}}}{R}t\] \[=\frac{{{(220)}^{2}}}{\frac{{{(220)}^{2}}}{500}}=500t\] \[{{H}_{2}}=\frac{{{(220)}^{2}}}{\frac{{{(220)}^{2}}}{200}}t=200t\] \[\frac{{{H}_{1}}}{{{H}_{2}}}=\frac{500t}{200t}=\frac{5}{2}\] In series \[{{H}_{1}}={{I}^{2}}RT\] \[={{I}^{2}}\frac{{{(220)}^{2}}}{500}\times t\] \[=\frac{{{(220)}^{2}}}{200}t\] \[=\frac{{{(220)}^{2}}}{500}\times \frac{200}{{{(220)}^{2}}}\] \[\frac{{{H}_{1}}}{{{H}_{2}}}=\frac{2}{5}\]You need to login to perform this action.
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