A) 1mH
B) 10 mH
C) 100 mH
D) 1000 mH
Correct Answer: A
Solution :
Given, \[e=100mV=100\times {{10}^{-3}}V\] \[dI=10-0=10A,\] \[dt=0.1s\] So, coefficient of mutual inductance \[M=\frac{e}{dI/dt}=\frac{100\times {{10}^{-3}}}{10/0.1}\] \[={{10}^{-3}}H=1mH\]You need to login to perform this action.
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