A) 4.55 A
B) 0.355 A
C) 0.455 A
D) 3.55 A
Correct Answer: C
Solution :
Given, \[{{V}_{L}}=120volt,\] \[L=0.70H,\] \[f=60Hz\] \[\therefore \]current passing through inductor \[{{I}_{L}}=\frac{{{V}_{L}}}{{{X}_{L}}}=\frac{{{V}_{L}}}{\omega L}=\frac{{{V}_{L}}}{2\pi fL}\] \[=\frac{120}{2\pi \times 60\times 0.70}=0.455A\]You need to login to perform this action.
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