A) 0.5
B) 5.0
C) 2.0
D) 8.0
Correct Answer: A
Solution :
EMF of cell \[E=I(R+r)\]when it is short circuited \[R=0\] So, internal resistance \[r=\frac{E}{I}=\frac{2}{4}=0.5\Omega \]You need to login to perform this action.
You will be redirected in
3 sec