A) 20N/C
B) 500 N/C
C) 5 N/C
D) 250 N/C
Correct Answer: B
Solution :
Electric field between the plates \[E=\frac{V}{d}=\frac{10}{2\times {{10}^{-2}}}\] \[=500N/C\]You need to login to perform this action.
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