A) \[HCN\]
B) \[N{{H}_{2}}N{{H}_{2}}\]
C) \[N{{H}_{2}}OH\]
D) \[N{{H}_{3}}\]
Correct Answer: D
Solution :
\[N{{H}_{3}}\] react with \[HCHO\].\[C{{H}_{3}}CHO\]and\[C{{H}_{3}}COC{{H}_{3}},\] give different product. (i) \[6HCHO+4N{{H}_{3}}\xrightarrow{{}}\underset{urotropine}{\mathop{{{(C{{H}_{2}})}_{6}}{{N}_{4}}}}\,+6{{H}_{2}}O\] (ii) (iii)You need to login to perform this action.
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