A) 3/2 g
B) g/3
C) 2/3 g
D) g
Correct Answer: B
Solution :
According to the question \[\frac{{{W}_{1}}}{{{W}_{2}}}=\frac{mg}{m(g-a)}=\frac{3}{2}\] or \[\frac{g}{g-a}=\frac{3}{2}\] \[\Rightarrow \] \[a=\frac{g}{3}m/{{s}^{2}}\]You need to login to perform this action.
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