A) 2:\[\sqrt{2}\]
B) \[\sqrt{2}\]:2
C) 1:1
D) 1 : 2
Correct Answer: C
Solution :
Young's modulus of elasticity is given by \[Y=\frac{mgL}{\pi {{r}^{2}}l}\] For two wires of same material and stretched by same force \[\frac{{{l}_{1}}}{{{l}_{2}}}=\frac{{{L}_{1}}}{{{L}_{2}}}\frac{r_{2}^{2}}{r_{1}^{2}}\] Given \[\frac{{{L}_{1}}}{{{L}_{2}}}=\frac{1}{2},\] \[\frac{{{r}_{1}}}{{{r}_{2}}}=\frac{1}{\sqrt{2}}\] \[\therefore \] \[\frac{{{l}_{1}}}{{{l}_{2}}}=\frac{1}{2}\times \frac{2}{1}=1:1\]You need to login to perform this action.
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