A) 200, 400
B) 205,410
C) 195, 390
D) 100, 200
Correct Answer: A
Solution :
Each fork produces 5 beat with its near fork. So, total number of beats \[=40\times 5=200\] If \[{{n}_{1}}\] and \[{{n}_{2}}\]are the frequencies of first and last fork then \[{{n}_{2}}-{{n}_{1}}=200\] ... (i) By the question \[{{n}_{2}}=2{{n}_{1}}\] ...(ii) Solving Eqs. (i) and (ii), we get \[{{n}_{1}}=200Hz,\] \[{{n}_{2}}=400Hz\]You need to login to perform this action.
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