A) \[_{\text{a}}{{\text{ }\!\!\mu\!\!\text{ }}_{\text{r}}}{{\text{=}}_{\text{a}}}{{\text{ }\!\!\mu\!\!\text{ }}_{\text{w}}}\,\text{ }\!\!\times\!\!\text{ }{{\,}_{\text{r}}}{{\text{ }\!\!\mu\!\!\text{ }}_{\text{w}}}\]
B) \[_{\text{a}}{{\text{ }\!\!\mu\!\!\text{ }}_{\text{r}}}{{\times }_{\text{a}}}{{\mu }_{w}}\,{{=}_{\text{w}}}{{\text{ }\!\!\mu\!\!\text{ }}_{\text{a}}}\]
C) \[_{a}{{\text{ }\!\!\mu\!\!\text{ }}_{\text{r}}}/{{ }_{r}}{{\mu }_{a}}\,=0\]
D) \[_{\text{a}}{{\text{ }\!\!\mu\!\!\text{ }}_{\text{r}}}/{{ }_{w}}{{\mu }_{r}}\,{{=}_{a}}{{\text{ }\!\!\mu\!\!\text{ }}_{w}}\]
Correct Answer: D
Solution :
When going through the option, we see that \[\frac{_{a}{{\mu }_{r}}}{_{w}{{\mu }_{r}}}=\frac{{{\mu }_{r}}/{{\mu }_{a}}}{{{\mu }_{r}}/{{\mu }_{w}}}=\frac{{{\mu }_{w}}}{{{\mu }_{a}}}{{=}_{a}}{{\mu }_{w}}\]You need to login to perform this action.
You will be redirected in
3 sec