A) Inductance
B) Reactance
C) Capacitance
D) Resistance
Correct Answer: A
Solution :
Dimensions corresponding with \[kg\text{-}{{\text{m}}^{2}}{{A}^{-2}}{{T}^{-2}}\] \[[M{{L}^{2}}{{A}^{-2}}{{T}^{-2}}]\] Inductance \[(L)={e}/{\frac{dI}{dt}}\;\] \[=\frac{[M{{L}^{2}}{{A}^{-2}}{{T}^{-2}}]}{[AT]}\times \frac{[T]}{[A]}\] \[=[M{{L}^{2}}{{T}^{-2}}{{A}^{-2}}]\] \[\therefore \] Unit of inductance can be written as \[kg\text{-}{{\text{m}}^{2}}{{A}^{-2}}{{T}^{-2}}\].You need to login to perform this action.
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