A) \[100{}^\circ \]
B) \[50{}^\circ \]
C) \[25{}^\circ \]
D) \[10{}^\circ \]
Correct Answer: C
Solution :
Given, \[{{f}_{o}}=100cm,\] \[{{f}_{e}}=2cm\] Visual angle subtended by moon \[(\alpha )={{0.5}^{o}}\] Visual angle subtended at eye with moon's image \[(\beta )=?\] Magnifying power of telescope \[(M)=\frac{\beta }{\alpha }=\frac{{{f}_{o}}}{{{f}_{e}}}\] \[\therefore \] \[\beta =\alpha .\,\frac{{{f}_{o}}}{{{f}_{e}}}=0.5\times \frac{100}{2}={{25}^{o}}\]You need to login to perform this action.
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