A) \[5\times {{10}^{-3}}N/m\]
B) \[5\times {{10}^{-2}}N/m\]
C) 5 N/m
D) 50 N/m
Correct Answer: B
Solution :
Given, \[r=2\times {{10}^{-3}}m.\] \[F=W=V\rho g=6.28\times {{10}^{-4}}m\] Surface tension \[(T)=\frac{F}{2\pi r}=\frac{6.28\times {{10}^{-4}}}{2\times 3.14\times 2\times {{10}^{-3}}}\] \[=0.05N/m=5\times {{10}^{-2}}N/m\]You need to login to perform this action.
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