A) atmosphere
B) \[atmospher{{e}^{2}}\]
C) \[atmospher{{e}^{-1}}\]
D) None of these
Correct Answer: A
Solution :
\[{{N}_{2}}{{O}_{4}}2N{{O}_{2}}-Q\] Applying law of mass action, \[{{K}_{P}}=\frac{{{(pN{{O}_{2}})}^{2}}}{P({{N}_{2}}{{O}_{4}})}\] \[{{K}_{P}}=\frac{{{(atmosphere)}^{2}}}{atmosphere}\] \[\therefore \] Unit of \[{{K}_{P}}\] is atmosphere.You need to login to perform this action.
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