A) 2ms
B) 12ms
C) 32ms
D) 500s
Correct Answer: A
Solution :
\[L=8mH=8\times {{10}^{-3}}H,\] \[R=4\Omega \] Time constant of L-R circuit \[=\frac{L}{R}=\frac{8\times {{10}^{-3}}}{4}\] \[=2\times {{10}^{-3}}s.\] \[=2ms\]You need to login to perform this action.
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