A) \[2\]
B) \[4\]
C) \[3\]
D) \[1\]
Correct Answer: C
Solution :
Ionization of \[[Co{{(N{{H}_{3}})}_{4}}Cl]C{{l}_{2}}\] is as follows \[[Co{{(N{{H}_{3}})}_{4}}Cl]C{{l}_{2}}{{[Co{{(N{{H}_{3}})}_{4}}Cl]}^{2+}}+2C{{l}^{-a}}\]It give three ions.
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