A) \[2.14V\]
B) \[1.80V\]
C) \[0.82V\]
D) \[1.07V\]
Correct Answer: D
Solution :
Cell reaction of given cell is \[Zn\xrightarrow{{}}Z{{n}^{2+}}(1\,M)+2{{e}^{-}}\] \[\underline{C{{u}^{2+}}(0.1M)+2{{e}^{-}}\xrightarrow{{}}Cu}\] Overall reaction \[=Zn+C{{u}^{2+}}(0.1M)\xrightarrow{{}}\] \[Cu+Z{{n}^{2+}}(1M)\] \[{{E}_{cell}}=E_{cell}^{o}+\frac{2.303RT}{nF}\log \frac{[C{{u}^{2+}}]}{[Z{{n}^{2+}}]}\] \[=1.10+\frac{0.0591}{2}\log \frac{0.1}{1}\] \[=1.10+0.0295\times (-1)\] \[\therefore \] \[{{E}_{cell}}=1.0705V\]You need to login to perform this action.
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