A) 15 min
B) 30 min
C) 45 min
D) None of these
Correct Answer: B
Solution :
For a radioactive substance \[N={{N}_{0}}{{\left( \frac{1}{2} \right)}^{n}}\] \[\frac{{{N}_{0}}}{16}={{N}_{0}}{{\left( \frac{1}{2} \right)}^{n}}\] \[\therefore \] \[n=4\] \[\because \] \[t=n\times T\] \[\therefore \] \[T=\frac{t}{n}=\frac{2}{4}h\] \[=\frac{2\times 60}{4}\min =30\min \]
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