A) 20 W
B) 40 W
C) 1000 W
D) zero
Correct Answer: D
Solution :
\[I=5\sin (100t-\pi /2)\] \[V=200\,\sin \,100t\] Phase difference between alternating current and alternating voltage is \[\pi /2\]. \[\therefore \] Power consumption \[(\bar{P})={{V}_{rms}}.{{I}_{rms}}.\cos \frac{\pi }{2}\]\[=0\]You need to login to perform this action.
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