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Chhattisgarh PMT Chhattisgarh PMT Solved Paper-2007

  • question_answer
    Emf of generator is 6V and internal resistance is 0.5\[k\,\Omega .\] If internal resistance of voltmeter is 2.5 \[k\,\Omega .\] then reading of voltmeter must be

    A)  10-3V                                    

    B)  1V

    C)  5V                                         

    D)  10 V

    Correct Answer: C

    Solution :

    Current flowing through the circuit \[I=\frac{V}{R+G}\] \[=\frac{6}{(2.5+0.5)\times 1000}=\frac{1}{500}A\] \[\therefore \] Reading of voltmeter,                 \[V=I\times G=\frac{1}{500}\times 2.5\times 1000=5volt\]


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