A) 330 Hz
B) 220 Hz
C) 110 Hz
D) 440 Hz
Correct Answer: B
Solution :
Given \[{{v}_{1}}=300vib/s.\] Let \[{{l}_{1}}=l,\] \[\therefore \] \[{{l}_{2}}=3l\] \[{{T}_{1}}=T,\] \[\therefore \] \[{{T}_{2}}=4T\] \[{{v}_{1}}=\frac{1}{2l}\sqrt{\frac{T}{m}}=330\] ?.(i) In second case \[{{v}_{2}}=\frac{1}{2{{l}_{2}}}\sqrt{\frac{{{T}_{2}}}{m}}=\frac{1}{2(3l)}\sqrt{\frac{4T}{m}}\] \[{{v}_{2}}=\frac{2}{3}\times \frac{1}{2l}\sqrt{\frac{T}{m}}\] \[=\frac{2}{3}{{v}_{1}}\] \[=\frac{2}{3}\times 330=220Hz\]You need to login to perform this action.
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