A) 16.11 A
B) 1.611 A
C) 0.1611 A
D) 2.6 A
Correct Answer: B
Solution :
Total emf \[~=2\times 1.45=2.90\text{ }V\] Total internal resistance of the cells \[0.15+0.15=0.30\Omega \] Current in the filament \[(I)=\frac{E}{R+r}\] \[=\frac{2.90}{1.5+0.30}\] \[1.611A\]You need to login to perform this action.
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