A) \[25\,\Omega \]
B) \[35\,\Omega \]
C) \[10\,\Omega \]
D) \[5\,\Omega \]
Correct Answer: D
Solution :
\[{{R}_{1}}=5\Omega \] and \[{{R}_{2}}=5\Omega \] resistances are in series, \[\therefore \] \[R'=5+5=10\Omega \] \[R'\] and \[{{R}_{3}}=10\Omega \] are in parallel \[\frac{1}{R'\,'}=\frac{1}{10}+\frac{1}{10}=\frac{2}{10}=\frac{1}{5}\] \[R''=5\Omega \] Now,\[R'\,'\] and \[{{R}_{4}}=5\Omega \]are in series \[\therefore \] \[R'\,'\,'=5+5=10\Omega \] Now, \[{{R}_{5}}\] and \[R'\,'\,'\] are in parallel, \[\therefore \] \[\frac{1}{R}=\frac{1}{10}+\frac{1}{10}=\frac{2}{10}=\frac{1}{5}\] \[\therefore \] \[R=5\Omega \]You need to login to perform this action.
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