Chhattisgarh PMT Chhattisgarh PMT Solved Paper-2007

  • question_answer
    A constant torque acting on a uniform circular wheel changes its angular momentum from \[{{\text{A}}_{\text{0}}}\] to \[\text{4}{{\text{A}}_{\text{0}}}\] in 4 s. The magnitude of this torque is

    A) \[\frac{3{{A}_{0}}}{4}\]                                 

    B)  \[{{A}_{0}}\]

    C) \[4{{A}_{0}}\]                                   

    D) \[121{{A}_{0}}\]

    Correct Answer: A

    Solution :

    Change in angular momentum \[=4{{A}_{0}}-{{A}_{0}}\] \[\Delta L=3{{A}_{0}}\] Torque,         \[\tau =\frac{\Delta L}{\Delta t}\]                                 \[\tau =\frac{3{{A}_{0}}}{4}\]


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