A) ammonium nitrate
B) \[N{{O}_{2}}\]
C) \[NO\]
D) \[{{N}_{2}}O\]
Correct Answer: A
Solution :
Zinc reacts with very dilute nitric acid gives zinc nitrate and ammonium nitrate. \[\begin{align} & [Zn+2HN{{O}_{3}}\xrightarrow{{}}Zn{{(N{{O}_{3}})}_{2}}+2H]\times 4 \\ & HN{{O}_{3}}+8H\xrightarrow{{}}N{{H}_{3}}+3{{H}_{2}}O \\ & 2NaI+HN{{O}_{3}}\xrightarrow{{}}N{{H}_{4}}N{{O}_{3}} \\ & \_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_ \\ & 4Zn+10HN{{O}_{3}}\xrightarrow{{}}4Zn{{(N{{O}_{3}})}_{2}}+N{{H}_{4}}N{{O}_{3}}+3{{H}_{2}}O \\ \end{align}\]
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