A) -5.0D
B) -0.5D
C) +2D
D) -2D
Correct Answer: D
Solution :
Here \[v=-50\text{ }cm,\] \[v=\infty \] \[\frac{1}{f}=\frac{1}{v}-\frac{1}{u}\] \[=\frac{1}{-50}-\frac{1}{\infty }=-\frac{1}{50}\] \[\therefore \] \[f=-50cm=-\frac{50}{100}m=-\frac{1}{2}m\] Power of the lens \[=\frac{1}{f}=-2D\]You need to login to perform this action.
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