A) m/2
B) 2m
C) 3m
D) 4m
Correct Answer: B
Solution :
Minimum magnifying power of a telescope is \[m=-\frac{{{f}_{o}}}{{{f}_{e}}}\] when focal length of eye piece in halved, then \[m'=-\frac{{{f}_{o}}}{({{f}_{e}}/2)}=-2\frac{{{f}_{o}}}{{{f}_{e}}}\] \[m'=2m\]You need to login to perform this action.
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