A) n-type
B) p-type
C) intrinsic
D) p-n-p type
Correct Answer: A
Solution :
\[{{n}_{e}}=8\times {{10}^{14}}/c{{m}^{3}}\] \[{{n}_{h}}=5\times {{10}^{12}}/c{{m}^{3}}\] As \[{{n}_{e}}>{{n}_{h}}\] Therefore, the given semiconductor is a n-type semiconductor.You need to login to perform this action.
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