A) \[{{S}_{2}}O_{4}^{2-}<SO_{3}^{2-}<{{S}_{2}}O_{6}^{2-}\]
B) \[SO_{3}^{2-}<{{S}_{2}}O_{4}^{2-}<{{S}_{2}}O_{6}^{2-}\]
C) \[{{S}_{2}}O_{4}^{2-}<{{S}_{2}}O_{6}^{2-}<SO_{3}^{2-}\]
D) \[{{S}_{2}}O_{6}^{2-}<{{S}_{2}}O_{4}^{2-}<SO_{3}^{2-}\]
Correct Answer: A
Solution :
Let us consider oxidation number of S is x In \[SO_{3}^{2-},\] oxidation number of S, \[\Rightarrow \] \[x+(-2)\times 3=-2\] \[\Rightarrow \] \[x=-2+6\] \[\therefore \] \[x=+4\] In \[{{S}_{2}}O_{4}^{2-}\] oxidation number of S \[\Rightarrow \] \[2\times x+(-2)\times 4=-2\] \[\Rightarrow \] \[2x=-2+8\] \[\therefore \] \[x=+3\] In \[{{S}_{2}}O_{6}^{2-}\]-oxidation number of S \[\Rightarrow \] \[2x+(-2)\times 6=-2\] \[\Rightarrow \] \[2x=-2+12\] \[\therefore \] \[x=+5\]You need to login to perform this action.
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