A) 20 N
B) 30 N
C) 60 N
D) 120 N
Correct Answer: C
Solution :
Given,\[A=3m{{m}^{2}}=3\times {{10}^{-6}}{{m}^{2}}\] \[\alpha ={{10}^{-5}}^{o}{{C}^{-1}},\] \[Y=2\times {{10}^{11}}N/{{m}^{2}}\] \[\Delta t={{(20-10)}^{o}}C\] \[={{10}^{o}}C\] Tension in the wire \[F=YA\,\alpha \,\Delta t\] \[=2\times {{10}^{11}}\times 3\times {{10}^{-6}}\times {{10}^{-5}}\times 10\] \[=60N\]You need to login to perform this action.
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