A) 10 V
B) -10 V
C) -43V
D) -33V
Correct Answer: A
Solution :
\[\phi =5{{t}^{2}}+3t+16\] Induced emf \[(e)=\frac{-d\phi }{dt}=-[10t+3+0]\] Induced emf in 4 s, \[{{e}_{4}}=-10\times 4-3=-43V\] Induced emf in 3 s. \[{{e}_{3}}=-10\times 3-3=-33V\] \[\therefore \] Induced emf in 4th \[\sec ={{l}_{4}}\tilde{\ }{{l}_{3}}\] \[=43\tilde{\ }(33)\] \[=10V\]You need to login to perform this action.
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